Help po kong paano ma sasagot po eto the current I varies directly as the electromotive force E and inversely as the resistance R. If a current of 30 amperes flows through a system with 16 ohms resistance and electromotive force a 120 volts,find the current when the current when the system with 20 ohms resistance and electromotive force of 200 volt.the current I varies directly as the electromotive force E and inversely as the resistance R. If a current of 30 amperes flows through a system with 16 ohms resistance and electromotive force a 120 volts,find the current when the current when the system with 20 ohms resistance and electromotive force of 200 volt.
I = kE/R
30 = 120k/16
k=4
Now you can answer the question when you have fixed the typos.
is it okay if i copy the answer?<3
To solve this problem, we can use the concept of direct and inverse variation.
First, let's define the given information:
- Current (I) varies directly with electromotive force (E)
- Current (I) varies inversely with resistance (R)
- Current (I) = 30 amperes
- Resistance (R) = 16 ohms
- Electromotive force (E) = 120 volts
To find the current when the resistance is 20 ohms and the electromotive force is 200 volts, we can set up a proportion using the direct and inverse variation concept:
I₁ / I₂ = (E₁ / E₂) * (R₂ / R₁)
Where:
- I₁ is the current for the first system (30 amperes)
- I₂ is the unknown current we want to find
- E₁ is the electromotive force for the first system (120 volts)
- E₂ is the given electromotive force for the second system (200 volts)
- R₁ is the resistance for the first system (16 ohms)
- R₂ is the given resistance for the second system (20 ohms)
Now, let's substitute the given values into the proportion:
30 / I₂ = (120 / 200) * (20 / 16)
Simplifying the proportion:
30 / I₂ = 0.6 * 1.25
30 / I₂ = 0.75
Multiply both sides by I₂:
30 = 0.75 * I₂
Divide both sides by 0.75:
I₂ = 40
Therefore, the current when the system has a resistance of 20 ohms and an electromotive force of 200 volts is 40 amperes.