Calculate the pH given the following H3O+ concentrations:
a) 2.3 x 10-6 M b) 8.3 x 10-9 M c) 6.4 x 10-3 M d) 4.1 x 10-7M
pH = -log(H3O)^+
Substitute into the above equation and solve for pH.
Post your work if you get stuck.
To calculate the pH given the H3O+ concentrations, we can use the formula:
pH = -log[H3O+]
a) For the H3O+ concentration of 2.3 x 10^(-6) M:
pH = -log(2.3 x 10^(-6))
To calculate this, you can use a scientific calculator or an online log calculator. The result is approximately 5.64.
b) For the H3O+ concentration of 8.3 x 10^(-9) M:
pH = -log(8.3 x 10^(-9))
Again, use a scientific calculator or an online log calculator to solve this. The result is approximately 8.08.
c) For the H3O+ concentration of 6.4 x 10^(-3) M:
pH = -log(6.4 x 10^(-3))
Using a calculator, the answer is approximately 2.19.
d) For the H3O+ concentration of 4.1 x 10^(-7) M:
pH = -log(4.1 x 10^(-7))
Using a calculator, the result is approximately 6.39.
Remember to always check your significant figures and round the answers to the appropriate number of decimal places based on the given data.