Write the Balanced Equation Skeleton:
KI (aq) + Pb(NO3)2 (aq) → KNO3 (aq) + PbI2 (s)
That looks good to me but since you have phases in the question I think you should included phases in the final equation.
You need 2KI
So it would be Pb(NO3)2+2kI → 2KNO3+ PbI2 ?
Thank you
To write the balanced equation skeleton, we need to account for the number of atoms of each element on both sides of the equation. Here's how you can do it step by step:
Step 1: Write the chemical formulas of the reactants and the products.
KI (aq) + Pb(NO3)2 (aq) → KNO3 (aq) + PbI2 (s)
Step 2: Break down any compounds with polyatomic ions into their individual ions.
KI (aq) breaks down into K⁺ (aq) and I⁻ (aq)
Pb(NO3)2 (aq) breaks down into Pb²⁺ (aq) and 2NO3⁻ (aq)
Step 3: Write down the new ionic compounds formed after the ions break apart.
KI (aq) becomes K⁺ (aq) + I⁻ (aq)
Pb(NO3)2 (aq) becomes Pb²⁺ (aq) + 2NO3⁻ (aq)
Step 4: Balance the equation by making sure the number of atoms of each element is the same on both sides.
2KI (aq) + Pb(NO3)2 (aq) → 2KNO3 (aq) + PbI2 (s)
And that is the balanced equation skeleton for the given chemical reaction:
2KI (aq) + Pb(NO3)2 (aq) → 2KNO3 (aq) + PbI2 (s)