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A metal X forms two different chlorides. If 12.7g of chlorine A and 16.3g of chloride B contain 7.1g and 10.7g of chlorine respectively, show that the figures agree with the law of multiple proportions. Write their formulae

Check those numbers. I think you may have transposed the g Cl

Did you know?

Did you know that the Law of Multiple Proportions states that when two elements combine to form more than one compound, the ratio of the masses of one element that combines with a fixed mass of the other element can be expressed in small whole numbers? In this case, metal X forms two different chlorides: chloride A and chloride B. Given that 12.7g of chlorine A contains 7.1g of chlorine, and 16.3g of chlorine B contains 10.7g of chlorine, we can see that the ratio of chlorine to metal X in chloride A is approximately 1.79:1, and in chloride B it is approximately 1.53:1. These ratios are close to small whole numbers, indicating that the figures agree with the law of multiple proportions. Based on this, the formula for chloride A can be represented as XCl₂, and the formula for chloride B can be represented as XCl₃, where X represents the metal.