naoh+ h2so4 ionic equation
naoh+ h2so4 ionic equation
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
Complete ionic equation is---
2Na^+(aq) + 2OH^-(aq) + 2H^+(aq) + [SO4]^2-(aq) ==> 2Na^+(aq) + [SO4]^2- + 2H2O(l)
net ionic equation is -----
2OH^-(aq) + 2H^+(aq) ==> 2H2O(l)
naoh+ h2so4 ionic equation
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
Complete ionic equation is---
2Na^+(aq) + 2OH^-(aq) + 2H^+(aq) + [SO4]^2-(aq) ==> 2Na^+(aq) + [SO4]^2- + 2H2O(l)
net ionic equation is -----
2OH^-(aq) + 2H^+(aq) ==> 2H2O(l)
their u gooo just sayin' i did not copy off of drbob222, i solved it myself
To write the ionic equation for the reaction between NaOH and H2SO4, we first need to write the balanced chemical equation.
The balanced chemical equation for the reaction is:
2NaOH + H2SO4 -> Na2SO4 + 2H2O
Now, we can determine the ionic equation by separating the soluble compounds into their respective ions. In this case, NaOH and H2SO4 are both soluble compounds, so they will dissociate into their constituent ions:
NaOH -> Na+ + OH-
H2SO4 -> 2H+ + SO4^2-
The ionic equation for the reaction is then:
2Na+ + 2OH- + 2H+ + SO4^2- -> 2Na+ + SO4^2- + 2H2O
Simplifying further, we get:
2OH- + 2H+ -> 2H2O
This is the final ionic equation for the reaction between NaOH and H2SO4.
To determine the ionic equation for the reaction between NaOH (sodium hydroxide) and H2SO4 (sulfuric acid), we need to first write the balanced chemical equation for the reaction.
The balanced equation for the reaction between NaOH and H2SO4 is:
2NaOH + H2SO4 -> Na2SO4 + 2H2O
Now, let's break down the equation into its ionic components:
2Na+ + 2OH- + H+ + SO4^2- -> Na2SO4 + 2H2O
In this equation, Na+ and OH- ions come from the dissociation of NaOH, while H+ and SO4^2- ions come from the dissociation of H2SO4.
The ionic equation for the reaction is:
2Na+ + 2OH- + H+ + SO4^2- -> Na2SO4 + 2H2O
Note that the spectator ions, Na+ and SO4^2-, are identical on both sides of the equation and do not participate in the actual reaction.