If you start with 100 g of Ba(NO3)2 and make a saturated solution in water at 100oC, how much water is required?
To find out how much water is required to make a saturated solution of Ba(NO3)2 at 100°C, we need to know the solubility of the compound at that temperature. The solubility of a substance refers to the maximum amount of that substance that can dissolve in a given amount of solvent at a specific temperature.
In this case, we need to determine the solubility of Ba(NO3)2 at 100°C. Once we know this value, we can calculate the amount of water required to dissolve 100 g of Ba(NO3)2.
One way to determine the solubility is to consult a solubility chart or look up the experimental data for Ba(NO3)2 at 100°C.
Let's assume that the solubility of Ba(NO3)2 at 100°C is 120 g/100 g of water. This means that 100 g of water can dissolve 120 g of Ba(NO3)2 at that temperature.
To find the amount of water needed to dissolve 100 g of Ba(NO3)2, we will use the ratio of solute to solvent.
Since the solubility is given as 120 g of Ba(NO3)2 per 100 g of water, we can set up the following equation:
120 g Ba(NO3)2/100 g water = 100 g Ba(NO3)2/x g water
Solving for x, we can find the amount of water required. Rearranging the equation:
x = (100 g Ba(NO3)2*100 g water) / 120 g Ba(NO3)2
x = 83.33 g water
Therefore, approximately 83.33 grams of water are required to make a saturated solution of Ba(NO3)2 at 100°C when starting with 100 grams of the compound.