A wire in the shape of a circle encloses the area 40cm2. If the wire is rebent to form a square, find the area of the square.
πr^2 = 40
C = 2πr = 2√(40/π)
s = C/4 = 1/2 √(40/π)
so A = s^2 = 1/4 * 40/π = 10/π
C = 2πr = 2√(40/π)
s = C/4 = 1/2 √(40/π)
so A = s^2 = 1/4 * 40/π = 10/π