Balance this chemical equation for this reaction.
NaOH + KHC8H4O4 ---> ?
NaOH + KHC8H4O4 ---> KNaC8H4O4 + H2O
NaOH + KHC8H4O4 = NaKC8H4O4 + H2O
Now it's NaKC8H4O4 because NaOH and KHC8H4O4 didn't want to be the odd ones out. They decided to hang out together and become a new compound, NaKC8H4O4! And let's not forget about H2O - it just couldn't resist joining the party. So there you have it, the perfectly balanced chemical equation with a touch of sodium, potassium, hydroxide, and some good old-fashioned humor!
To balance the chemical equation for the reaction between NaOH and KHC8H4O4, follow these steps:
Step 1: Write down the unbalanced equation:
NaOH + KHC8H4O4 ---> ?
Step 2: Count the number of atoms for each element on both sides of the equation. At this stage, we have:
Na: 1 on the left, 0 on the right.
H: 1 on the left, 10 on the right.
O: 1 on the left, 4 on the right.
K: 1 on the left, 0 on the right.
C: 0 on the left, 8 on the right.
Step 3: Begin balancing the equation by adjusting coefficients in front of the molecules or compounds. In this case, let's balance the number of hydrogen atoms first.
Looking at the hydrogen atoms, there are 1 on the left and 10 on the right. To equalize the number of hydrogen atoms, we need a coefficient of 10 in front of NaOH:
10 NaOH + KHC8H4O4 ---> ?
Now, the equation is:
10 NaOH + KHC8H4O4 ---> ?
Step 4: Check the elements again.
Na: 10 on the left, 0 on the right.
H: 10 on the left, 10 on the right.
O: 10 on the left, 4 on the right.
K: 1 on the left, 0 on the right.
C: 0 on the left, 8 on the right.
Step 5: Balance the remaining atoms, starting with potassium (K). As potassium appears only on the left side, it already has a coefficient of 1. So, we can skip balancing it further.
10 NaOH + KHC8H4O4 ---> ?
Step 6: Balance the carbon (C) atoms. As carbon appears only on the right side, we can balance it by adding a coefficient of 8 in front of KHC8H4O4:
10 NaOH + 8 KHC8H4O4 ---> ?
Now, the equation is:
10 NaOH + 8 KHC8H4O4 ---> ?
Step 7: Check the elements again.
Na: 10 on the left, 0 on the right.
H: 10 on the left, 10 on the right.
O: 10 on the left, 32 (8*4) on the right.
K: 8 on the left, 0 on the right.
C: 0 on the left, 64 (8*8) on the right.
All the elements are now balanced.
The balanced chemical equation for the reaction between NaOH and KHC8H4O4 is:
10 NaOH + 8 KHC8H4O4 ---> ?
To balance the chemical equation for this reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
The equation to balance is:
NaOH + KHC8H4O4 → ?
Let's break down the equation and count the number of atoms for each element:
1) Sodium (Na): There is one Na atom on the left side and zero on the right side.
2) Hydrogen (H): There is one H atom in NaOH and one in KHC8H4O4, so a total of two H atoms on the left side. On the right side, there are four H atoms from KHC8H4O4.
3) Oxygen (O): There are one O atom in NaOH and four in KHC8H4O4, so a total of five O atoms on the right side.
4) Potassium (K): There is one K atom in KHC8H4O4 on the left side and zero on the right side.
5) Carbon (C): There are eight C atoms in KHC8H4O4 on the left side and zero on the right side.
We can now balance the equation step by step:
NaOH + KHC8H4O4 → NaKC8H4O4 + H2O
1) Sodium (Na): We balanced the Na by adding it to the right side, forming NaKC8H4O4.
2) Hydrogen (H): We balance the H by adding H2O on the right side.
3) Oxygen (O): We balance the O by adjusting the coefficients to have five O atoms on each side. Since we added a coefficient of 4 to H2O for the H atoms, we need to multiply NaKC8H4O4 by 5 to have five O atoms, resulting in:
NaOH + KHC8H4O4 → 5NaKC8H4O4 + 4H2O
4) Potassium (K) and Carbon (C): Both elements are now balanced, as they are present only on the left side.
The balanced equation is:
NaOH + KHC8H4O4 → 5NaKC8H4O4 + 4H2O