How many
a) H+ ions (1 g-ion/L = 6.023 x 1023 ions/L) and
b) OH- ions are present in 250 ml of a solution of pH 3?
U look to me you are a student in Ankara
pH = 3 means (H^+) = 0.001 M or 10^-3 M
That is 0.001 mols/L so in 250 mL you have just 1/4 of that = 0.001 x (250/1000) = ?
# H^+ = ? from the line above x 6.02E23 = ??
To determine the number of H+ and OH- ions in a solution, we need to first understand the relationship between pH and the concentration of H+ ions.
pH is a measure of the acidity or basicity of a solution and is defined as the negative logarithm (base 10) of the concentration of H+ ions in moles per liter (M). The formula for pH is:
pH = -log[H+]
Given that the solution has a pH of 3, we can determine the concentration of H+ ions by rearranging the equation:
[H+] = 10^(-pH)
[H+] = 10^(-3)
Now, we can calculate the number of H+ ions in 250 ml (0.25 L) of the solution by using the molar concentration:
Number of H+ ions = [H+] x volume in liters
Number of H+ ions = 10^(-3) mol/L x 0.25 L
The calculation above gives us the number of H+ ions present in the solution.
Next, to determine the number of OH- ions, we should remember that water (H2O) can self-ionize. This self-ionization results in equal concentrations of H+ and OH- ions in pure water at standard conditions. However, in an acidic solution, the concentration of H+ ions is higher than that of OH- ions.
Considering the conservation of charge, we can use the equation:
[H+] x [OH-] = 1 x 10^(-14) M^2
Given that in pure water [H+] = [OH-] = 1 x 10^(-7) M, the above equation can be modified to:
[H+]^2 = 1 x 10^(-14)
Now we can solve for [OH-]:
[OH-] = 1 x 10^(-14) / [H+]
Using the value of [H+] we calculated earlier, we can determine the concentration of OH- ions in moles per liter.
Finally, we can calculate the number of OH- ions in 250 ml of the solution by multiplying the concentration by the volume in liters:
Number of OH- ions = [OH-] x volume in liters
Number of OH- ions = [OH-] x 0.25 L
Using the calculations above, you can find the number of H+ ions (a) and OH- ions (b) present in 250 ml of the solution.