Ethylene glycol, commonly used as automobile antifreeze, has a specific gravity of 1.1088 at room temperature (25 ℃). What is the mass of 1.00 L of ethylene glycol at this temperature?
To find the mass of 1.00 L of ethylene glycol at room temperature (25 ℃), we need to use the specific gravity of ethylene glycol.
Specific gravity is the ratio of the density of a substance to the density of a reference substance, usually water. In this case, the specific gravity of ethylene glycol is given as 1.1088.
Density is defined as mass per unit volume. So, we can use the specific gravity to calculate the density of ethylene glycol relative to water.
The density of water at 25 ℃ is approximately 1.00 g/mL. So, if the specific gravity of ethylene glycol is 1.1088, it means that ethylene glycol is 1.1088 times denser than water.
To find the density of ethylene glycol, we can multiply it by the density of water:
Density of ethylene glycol = 1.1088 * Density of water
Density of ethylene glycol = 1.1088 * 1.00 g/mL
Density of ethylene glycol = 1.1088 g/mL
Now, we can calculate the mass of 1.00 L (1000 mL) of ethylene glycol by multiplying the density by the volume:
Mass = Density * Volume
Mass = 1.1088 g/mL * 1000 mL
Mass = 1108.8 g
Therefore, the mass of 1.00 L of ethylene glycol at room temperature is 1108.8 grams.
Assuming it is 100% stuff,
mass = 1.1088 g/mL x 1000 mL = ?