You have 50 grams of steam that condenses on a cold surface. The steam goes from 100 degree C steam into 100 degree C liquid water. How much heat is involved?
are you in connexus
if not I can not help really
This is just a condensation and a phase change.
Steam @ 100 C to liquid H2O @ 100 C.
heat evolved = mass H2O x heat vaporization = ?
To calculate the amount of heat involved in the condensation process, we need to use the formula:
Q = m * ΔH
Where:
Q is the amount of heat involved,
m is the mass of the substance (in grams), and
ΔH is the heat of condensation (the amount of heat required to change one gram of steam into liquid water at the same temperature).
In this case, we have 50 grams of steam condensing into liquid water at the same temperature of 100 degrees Celsius. The heat of condensation for water is approximately 2260 J/g.
So, to calculate the heat involved, we can substitute the values into the formula:
Q = 50 grams * 2260 J/g
Now we can calculate using the given values:
Q = 113,000 J
Therefore, the amount of heat involved in the condensation of 50 grams of steam into liquid water at 100 degrees Celsius is 113,000 Joules.