A piece of metal has its temperature raised from 25.0 o C to 55.0 o C. The metal has a mass of 12.5 g. If 338 J of heat is absorbed, what is the specific heat of the metal?
q = mass metal x specific heat metal x (Tfinal - Tintial)
338 = 12.5 x specific heat metal x (55.0 - 25.0)
Solve for specific heat of metal