A mixture of 25.0g of NO and an excess of O2 reacts according to the balanced equation. 2 NO + O2→2NO2. How many liters of NO2 are produced at STP?

2NO + O2→2NO2

mols NO in 25 g = g/molar mass = 25/30 = approx 0.83
mols NO2 = 0.83 mols NO x (2 mols NO2/2 mol NO) = 0.83
0.83 mols x 22.4 L/mol @ STP = ?
You may want to check the numbers.

To calculate the volume of NO2 produced at STP (Standard Temperature and Pressure), we need to follow these steps:

Step 1: Calculate the number of moles of NO used.
To find the number of moles, we can use the mass and molar mass of NO.
The molar mass of NO is calculated as follows:
Molar mass of N = 14.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of NO = 14.01 + 16.00 = 30.01 g/mol

Number of moles = Mass / Molar mass
Number of moles of NO = 25.0 g / 30.01 g/mol (rounding to appropriate significant figures)

Step 2: Determine the ratio between NO and NO2 based on the balanced equation.
From the balanced equation, we can see that 2 mol of NO is equivalent to 2 mol of NO2.

Step 3: Calculate the number of moles of NO2 produced.
Since the ratio of NO to NO2 is 2:2, the number of moles of NO2 produced is the same as the number of moles of NO used.

Step 4: Calculate the volume of NO2 at STP.
At STP, 1 mole of gas occupies 22.4 liters.

Volume of NO2 = Number of moles of NO2 × 22.4 L/mol

Now, let's calculate the final answer:

Number of moles of NO = 25.0 g / 30.01 g/mol ≈ 0.833 mol
Number of moles of NO2 = Number of moles of NO = 0.833 mol
Volume of NO2 = 0.833 mol × 22.4 L/mol ≈ 18.62 L

Therefore, approximately 18.62 liters of NO2 will be produced at STP.

To find the number of liters of NO2 produced at STP, we need to use the given mass of NO and the balanced equation.

Step 1: Calculate the number of moles of NO.
To do this, we use the formula:
Number of moles = mass / molar mass

The molar mass of NO is the sum of the atomic masses of nitrogen (N) and oxygen (O):
Molar mass(NO) = (14.01 g/mol) + (16.00 g/mol) = 30.01 g/mol

Number of moles of NO = 25.0 g / 30.01 g/mol

Step 2: Use the stoichiometry (balanced equation) to determine the moles of NO2 produced.
According to the balanced equation, 2 moles of NO react to produce 2 moles of NO2.

Since the stoichiometry (ratio of reactants to products) is 1:1 for NO to NO2, the number of moles of NO2 produced will be the same as the number of moles of NO.

Number of moles of NO2 produced = Number of moles of NO

Step 3: Calculate the volume of NO2 at STP.
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters.

Volume of NO2 at STP = Number of moles of NO2 produced × 22.4 L/mol

Therefore, the number of liters of NO2 produced at STP can be calculated by multiplying the number of moles of NO by 22.4 L/mol.

Keep in mind that this calculation assumes the reaction goes to completion and that the given mass of NO is the limiting reactant.