Cr2o7-2+no-2=cr3++no-3
Cr2o7-2+no-2=cr3++no-3
1. I assume you mean [Cr2O7]^2- + [NO2]^- ==> Cr^3+ + [NO3]^-
2. I assume you want that balanced.
[Cr2O7]^2- + 3[NO2]^- + 8H^+ ==> 2Cr^3+ + 3[NO3]^- + 4H2O
3. Piece a cake.
The given equation is a redox reaction between Cr2O7-2 and NO-2, which produces Cr3+ and NO-3 ions. To balance this equation, we need to make sure that the number of atoms on both sides of the equation is equal and that the charges are balanced as well.
First, let's balance the oxygen atoms by adding water (H2O) molecules to the side that needs more oxygen. In this case, we need to add water molecules to the right side of the equation:
Cr2O7-2 + NO-2 → Cr3+ + NO-3
Next, balance the hydrogen atoms by adding hydrogen ions (H+) to the side that needs more hydrogen. In this case, we need to add hydrogen ions to the left side of the equation:
Cr2O7-2 + 14H+ + NO-2 → Cr3+ + NO-3
Now, let's balance the charges. We can do this by adding electrons (e-) to the side that needs a more negative charge. In this case, we need to add electrons to the left side of the equation:
Cr2O7-2 + 14H+ + 6e- + NO-2 → Cr3+ + NO-3
Finally, make sure that the number of electrons is equal on both sides. In this case, both sides have 6 electrons, so we don't need to make any further adjustments.
The balanced equation is:
Cr2O7-2 + 14H+ + 6e- + NO-2 → Cr3+ + NO-3