Hi i kind of get these questions but i got stuck on this...
What is the molarity of an H2SO4 solution if 0.25L of the solution contains 0.75L MOL of H2SO4? thanks again for yourself i really do appreciate it :)
Molarity= molessolute/litersolution
= .75/.25= 3M
I assume the .75L was a typo on the L.
Not to worry, I'm here to help you understand the question and how to find the answer!
To find the molarity of an H2SO4 solution, you need to use the formula:
Molarity = moles of solute / liters of solution
In this case, you are given that 0.25 liters of the solution contains 0.75 moles of H2SO4.
To calculate the molarity, simply divide the moles of the solute (which is 0.75 moles) by the liters of the solution (which is 0.25 liters):
Molarity = 0.75 moles / 0.25 liters
Simplifying this expression gives:
Molarity = 3 moles per liter (3M)
Therefore, the molarity of the H2SO4 solution is 3M.
It's important to note that in your question, you mentioned 0.75L as the amount of moles of H2SO4, but that seems to be a typo. The units for the amount of moles should be moles (mol) and not liters (L). You cannot have a volume (liters) represented as moles. Instead, the liters value is used in the denominator of the molarity formula to represent the volume of the solution.