Determine how to prepare 2.00 L of 0.157 M HCl solution from a 12.3 M stock HCl solution.
Use the dilution formula of
M1 x mL1 = M2 x mL2
12.3 x mL1 = 2,000 mL x 0.157
Solve for mL1 = the volume of 12.3 M HCl stock to add to a 2.00 L volumetric flask. Add distilled water to the flask and make to the mark, stopper, mix thoroughly, label.
To prepare 2.00 L of 0.157 M HCl solution from a 12.3 M stock HCl solution, you can follow these steps:
Step 1: Determine the volume of the stock solution needed.
Use the formula:
M1V1 = M2V2
Where:
M1 = initial concentration of the stock solution
V1 = initial volume of the stock solution
M2 = final concentration of the desired solution
V2 = final volume of the desired solution
Rearrange the formula to solve for V1:
V1 = (M2 × V2) / M1
Plugging in the values:
M1 = 12.3 M
V1 = ? (to be determined)
M2 = 0.157 M
V2 = 2.00 L
V1 = (0.157 M × 2.00 L) / 12.3 M
Calculate V1:
V1 = 0.0255 L (or 25.5 mL)
Step 2: Measure 25.5 mL of the stock HCl solution.
Use a graduated cylinder or a pipette to measure out 25.5 mL of the 12.3 M HCl stock solution.
Step 3: Dilute the stock solution to a total volume of 2.00 L.
Transfer the 25.5 mL of the stock HCl solution to a clean, empty container. Then, add enough water to reach a total volume of 2.00 L. You can use a volumetric flask to accurately measure the final volume.
Step 4: Mix well.
Thoroughly mix the contents of the container by gently swirling or stirring until the stock solution is fully diluted.
After following these steps, you will have prepared 2.00 L of 0.157 M HCl solution from the 12.3 M stock HCl solution.
To determine how to prepare a 2.00 L of 0.157 M HCl solution from a 12.3 M stock HCl solution, we need to use the equation:
M1V1 = M2V2
Where:
M1 = initial concentration of the stock solution
V1 = volume of the stock solution used
M2 = final concentration of the desired solution
V2 = final volume of the desired solution
In this case, we're given:
M1 = 12.3 M (stock solution concentration)
V1 = unknown (volume of stock solution to be used)
M2 = 0.157 M (desired concentration)
V2 = 2.00 L (desired volume)
Rearranging the equation to solve for V1:
V1 = (M2 * V2) / M1
Plugging the values:
V1 = (0.157 M * 2.00 L) / 12.3 M
V1 = 0.0255 L
Therefore, to prepare a 2.00 L of 0.157 M HCl solution from a 12.3 M stock HCl solution, you need to measure 0.0255 L (or 25.5 mL) of the stock solution and dilute it to 2.00 L with a suitable solvent, such as water.