Just want to make sure my calculations are correct.
If 3% H2O2 has a molarity of 0.88M, and the volume is 50.0mL, is the number of moles 0.044? Thank you :)
Looks OK to me.
To verify if your calculations are correct, let's go through the steps.
First, we need to calculate the number of moles of H2O2 using the given molarity and volume.
Molarity (M) is defined as moles of solute per liter of solution. Here, we have a volume of 50.0 mL, which we need to convert to liters.
1 L = 1000 mL
So, 50.0 mL = 50.0/1000 = 0.050 L
Now we can use the formula:
Molarity (M) = Moles (mol) / Volume (L)
Rearranging the formula, we have:
Moles (mol) = Molarity (M) * Volume (L)
Substituting the given values:
Moles (mol) = 0.88 M * 0.050 L
Calculating:
Moles (mol) = 0.044 mol
Therefore, the number of moles of H2O2 is indeed 0.044 mol.
Your calculations are correct!
To determine the number of moles of a substance, you need to use the formula:
Moles = Molarity × Volume (in liters)
In this case, you have a 3% H2O2 solution with a molarity of 0.88M and a volume of 50.0mL. However, the volume must be converted to liters because the molarity is given in moles per liter.
Converting 50.0 mL to liters:
50.0 mL ÷ 1000 mL/L = 0.05 L
Now, you can calculate the moles of H2O2:
Moles = 0.88M × 0.05 L = 0.044 moles
So, yes, your calculation of 0.044 moles is correct for the given parameters.