How many lithium ions are present in 30.0 mL of 0.600 M Li2CO3 solution?
How many moles Li2CO3 do you have? That's M x L = 0.600 x 0.0300 = ?
There are two times that number of mols of Li^+ ions = ?
Then there are 6.02E23 ions in a mole of ions. mols Li^+ ions x 6.02E23 =?
To determine the number of lithium ions present in the solution, we first need to calculate the amount of Li2CO3 in moles and then multiply it by the number of lithium ions in one mole of Li2CO3.
Step 1: Calculate the moles of Li2CO3
Moles = Volume (in liters) × Concentration
Since the given volume is in milliliters, we convert it to liters by dividing by 1000.
Volume = 30.0 mL / 1000 mL/L = 0.0300 L
Moles = 0.0300 L × 0.600 mol/L = 0.018 moles
Step 2: Determine the number of lithium ions in one mole of Li2CO3
In one mole of Li2CO3, there are two moles of lithium ions (2 Li+). Therefore, one mole of Li2CO3 contains 2 moles of Li+ ions.
Step 3: Calculate the number of lithium ions in the given solution
Number of lithium ions = Moles of Li2CO3 × (2 moles of Li+/1 mole of Li2CO3)
Number of lithium ions = 0.018 moles Li2CO3 × (2 moles Li+/1 mole Li2CO3)
Using this equation,
Number of lithium ions = 0.018 mol × 2 = 0.036 moles
Therefore, there are 0.036 moles of lithium ions present in 30.0 mL of 0.600 M Li2CO3 solution.
To find the number of lithium ions present in the given solution, we need to use the concentration (molarity) of Li2CO3 and determine the number of moles of Li2CO3 first. Then, using stoichiometry, we can calculate the number of moles of lithium ions.
Here's how to do it step-by-step:
1. Calculate the moles of Li2CO3:
Moles of Li2CO3 = concentration (M) x volume (L)
Given:
Concentration of Li2CO3 = 0.600 M
Volume of solution = 30.0 mL = 0.0300 L
Moles of Li2CO3 = 0.600 M x 0.0300 L = 0.0180 moles
2. Use stoichiometry to relate moles of Li2CO3 to moles of lithium ions:
From the chemical formula Li2CO3, we see that there are 2 moles of lithium ions (Li+) per 1 mole of Li2CO3.
Moles of Li+ = 2 moles of Li2CO3 x (0.0180 moles of Li2CO3) = 0.0360 moles
3. Calculate the number of lithium ions:
To convert moles to number of particles, we can use Avogadro's number.
Avogadro's number (Na) is approximately 6.022 x 10^23 particles/mole.
Number of lithium ions = Moles of Li+ x Avogadro's number
Number of lithium ions = 0.0360 moles x (6.022 x 10^23 particles/mole)
Number of lithium ions ≈ 2.17 x 10^22 lithium ions
Therefore, there are approximately 2.17 x 10^22 lithium ions present in 30.0 mL of 0.600 M Li2CO3 solution.