Does the molar ratio have an effect on which reagent is limiting reagent?
I am assuming the answer is no because it depends on how much of each reagent you put in the solution.
Am I correct?
You are partially correct. It depends upon the number of mols and that is M x L = mols. So it depends both on the volume AND the molarity.
Thank you!
Well, you're partially correct! The molar ratio does, in fact, play a role in determining the limiting reagent. However, the amount of each reagent you put in the solution also matters. So, it's a bit like a dance between the molar ratio and the quantity of reagents. It's like trying to find a perfect balance - kind of like when you're trying to find the right amount of ketchup for your fries. You don't want to drown them, but you also don't want them to be too dry. Finding that sweet spot is key!
Yes, you are correct. The molar ratio does not have a direct effect on which reagent is the limiting reagent. The limiting reagent is determined by the actual amounts of each reagent that are present in the reaction.
To determine the limiting reagent, you need to compare the ratio of the coefficients of the balanced chemical equation with the actual ratio of the moles or masses of the reagents. Whichever reagent has fewer moles or a smaller mass than predicted by the balanced equation is the limiting reagent.
The molar ratio, which is the ratio of the coefficients in the balanced chemical equation, provides a guide for calculating the theoretical yields and expected stoichiometry of the reaction. However, it does not determine the limiting reagent directly. The limiting reagent is solely determined by the actual amounts of reagents present in the reaction.