Find (f • g) when f(x)=√x-2 and g(x)= 6x-7
I got √-11x+14
Hmm. It appears that f(x) = √(x-2), so
(f•g)(x) = f(x)•g(x) = √(x-2) • (6x-7)
Maybe you meant
(f◦g)(x) = f(g(x)) = √(g-2) = √(6x-9)
How did you arrive at your answer?
I did this
F(6x-7)
√x-2(6x-7)
√x-12x+4
√-11x+14
√x-2(6x-7) = √x-2g
mighty weird, I must say.
Better read up on the distributive property and composition and multiplication of functions.
So the answer is √x-2g ?
To find the composition of two functions, denoted as (f • g)(x), you need to replace the x in f(x) with g(x).
Given:
f(x) = √x - 2
g(x) = 6x - 7
To find (f • g)(x), substitute g(x) into f(x), as follows:
f(g(x)) = √(g(x))-2
Replace g(x) with its expression:
f(g(x)) = √(6x-7)-2
So, (f • g)(x) = √(6x-7)-2.
It seems there might be an error in your calculation. Please check your work again.