An electric cell with nominal voltage E has a resistance of 3ohms connected across .if the voltage force to 0.6E,the internal resistance of the cell is?
To find the internal resistance of the cell, we can make use of Ohm's law and the concept of equivalent resistance.
According to Ohm's law, the voltage across a resistor can be calculated by multiplying the resistance (R) with the current (I) flowing through it. Mathematically, it can be represented as V = I * R.
In this case, the voltage across the cell is given as 0.6E, and the resistance connected across the cell is 3 ohms. The current flowing through the circuit can be found by dividing the voltage by the resistance: I = V / R.
Substituting the given values, we can calculate the current: I = (0.6E) / 3 = 0.2E.
Now that we know the current, we can calculate the voltage drop across the internal resistance of the cell. According to Ohm's law, the voltage drop (V_int) across the internal resistance (r) can be calculated by multiplying the current (I) with the resistance (r): V_int = I * r.
We are given the voltage drop across the cell as 0.6E, and we also know the current (0.2E). Substituting these values, we can calculate the internal resistance (r): 0.6E = (0.2E) * r.
Simplifying the equation, we find: r = 0.6E / (0.2E) = 3 ohms.
Therefore, the internal resistance of the cell is 3 ohms.