What volume (in L) of a 0.98 M solution of hydrochloric acid, a solution of HCl, can be prepared from the HCl produced by the reaction of 19.03 g of NaCl with an excess of sulfuric acid?
NaCl(s) + H2SO4(aq) = HCl(aq) + NaHSO4(s)
I don't understand how to solve this. Can someone please help explain? Thank you!
Never mind... I figured it out.
You have two problems here. The first is to determine the grams of HCl produced from the NaCl. The second problem is to determine the volume of that HCl produced to make a 0.98 M solution of HCl.
First.
.................NaCl(s) + H2SO4(aq) = HCl(aq) + NaHSO4(s)
mols NaCl = g/molar mass = 19.03/58.45 = 0.3256. That will make 0.3256 mols HCl.
Part 2. You want to make 0.98 mols/L HCl.
M = mols/L
mols of 0.98 = mols 0.3256 x L solution. Solve for L = about 3.0 L of the 0.3256 will be 0.98 M
Sure! I'd be happy to help you understand how to solve this problem.
To find the volume of the hydrochloric acid solution that can be prepared, we need to use stoichiometry and the given concentration of the solution.
Step 1: Calculate the moles of NaCl
To calculate the moles of NaCl, we need to use its molar mass. The molar mass of NaCl is 58.44 g/mol. We can calculate the moles using the formula:
moles of NaCl = mass of NaCl / molar mass of NaCl
In this case, the mass of NaCl is given as 19.03 g. Plugging this into the formula, we get:
moles of NaCl = 19.03 g / 58.44 g/mol
Step 2: Determine the stoichiometry of the reaction
From the balanced equation given, we can see that the reaction produces 1 mole of HCl for every 1 mole of NaCl. Therefore, the moles of HCl produced will also be 19.03 g / 58.44 g/mol.
Step 3: Find the volume of the HCl solution
The molarity (M) of a solution is defined as moles of solute per liter of solution. We can use this definition to find the volume of the HCl solution.
Molarity = moles of solute / volume of solution (in liters)
We are given the molarity of the HCl solution (0.98 M). Rearranging the equation, we can solve for the volume of the solution:
volume of solution = moles of solute / Molarity
Plugging in the values:
volume of solution = (19.03 g / 58.44 g/mol) / 0.98 M
To convert this to liters, we need to remember that 1 L = 1000 mL, so we can divide the result by 1000.
I hope this explanation helps you understand how to solve the problem!