Question

Would you expect the molar solubility of KIO4 to be greater in a 0.20 M NaNO3 solution or a 0.20 M KNO3 solution? Justify your answer.

Answer 1

The solubility of KIO4 is KIO4 ==> K+ + IO4^-

So Ksp = (K^+)(IO4^-)
You have the common ion effect if KNO3 is used and the addition of the K^+ from KNO3 will DECREASE the solubility of KIO4. So the solubility will be greater in a NaNO3 solution.