Mercury is commonly supplied in flasks containing 34.5 kg (about 76 lb) of the element, which has a density of 13.6 g/cm3. What is the volume, in liters, of this much mercury? correct sig figs
mass = volume x density.
Substitute the numbers in the problem and solve for volume in cc. Convert to L. Show your work if you get stuck.
do i have to use the 76lbs or could I just use the 34.5kg
ok sounds good. does anyone mind solving it out so that I can check my answer
i got 2.5L is that correct?
Yes, but the problem states the answer should be to the correct number of significant figures. You have three s.f. in 34.5 kg and 13.6 in g/cc so you can have 3 s.f. in your answer. 2.5 is two places.
oh yeah i forgot so it is 2.54L
right
m= v•d
34.5 kg= v(13.6 g/cm³)
•derive your equation to get the volume (v):
v= [34.5 kg/ (13.6 g/ cm³)]
•before solving, convert kg to g:
v= [(34, 500 g)/ (13.6 g/ cm³)]
= 2, 536.76 cm³
•covert in liters and round it off:
v= 2.5 L
To find the volume of mercury, we can use the formula:
Volume = Mass / Density
First, let's convert the given mass of mercury from kilograms to grams:
34.5 kg * 1000 g/kg = 34,500 g
Next, we can substitute the converted mass and the given density into the volume formula:
Volume = 34,500 g / 13.6 g/cm³
Now let's solve for the volume:
Volume ≈ 2,536.7647 cm³
To convert the volume from cubic centimeters (cm³) to liters, divide by 1000:
Volume = 2,536.7647 cm³ / 1000 = 2.5367647 liters
When considering significant figures, we look at the given value with the fewest significant figures, which in this case is "34.5 kg" (3 significant figures). Therefore, the final volume should be rounded to 3 significant figures.
Volume ≈ 2.54 liters
So, the volume of 34.5 kg of mercury is approximately 2.54 liters, considering correct significant figures.