integrate logx/x^2 from 1 to 2
my answer is
(-log2-1)/2
is it correct or not?????
I will assume you meant:
integrate ln x/x^2 from 1 to 2
∫ ln x/x^2 dx from 1 to 2
= -( lnx +1)/x | from 1 to 2
= -(ln2 + 1)/2 - (-(ln1 + 1)/1 )
= -ln2/2 -1/2 + (0 + 1)/1
= -ln2/2 + 1/2 or (-ln2 + 1)/2
check my work and check your work, one of us (or even both) is wrong