What is the solution to the quadratic equations in the graphs linked? Thanks!
1) imgur.com/4Vm7uQ0
2) imgur.com/VcEybYO
3) imgur.com/gCqO8iE
look for integer valued points, especially x-intercepts
In the first, I see (1,0) and (-6,0)
so the equation must be of the form
y = a(x - 1)(x + 6) = a(x^2 + 5x - 6)
another integer point seems to be (-4,-10), so sub that into my equation:
-10 = a(-4-1)(-4+6)
-10 = a(-10)
a = 1
so y = (x-1)(x+6) or y = x^2 + 5x - 6
do the others in the 2nd in the same way
For the third, it looks like the x-intercepts are 3 and -2.5 , and another integer point is (-2,-10)
proceed in the same way
Can I have answers for the other two as well? If that's not a bother, of course. I've accepted that I can never understand this stuff well enough to solve it. Thanks!
To find the solutions to the quadratic equations in the graphs provided, we can start by examining the x-intercepts or the points where the graph crosses the x-axis. In a quadratic equation, the x-intercepts represent the values of x for which the equation equals zero.
1) For the first graph (imgur.com/4Vm7uQ0), we can see that the x-intercepts are approximately x = -2 and x = 3. Therefore, the solutions to the corresponding quadratic equation are x = -2 and x = 3.
2) For the second graph (imgur.com/VcEybYO), there are no x-intercepts or points where the graph crosses the x-axis. This indicates that the quadratic equation has no real solutions. In other words, the equation has complex solutions or does not intersect the x-axis.
3) Lastly, for the third graph (imgur.com/gCqO8iE), we observe that the x-intercepts are approximately x = -3 and x = 5. Hence, the solutions to the quadratic equation are x = -3 and x = 5.
It's important to note that the accuracy of the solutions might vary slightly due to the approximate nature of the graphs. If you require a more precise answer, it is recommended to use numerical methods or algebraic techniques to solve the corresponding quadratic equations.