if absolute value of a negative number is 2.78,what is the distance on the number line between the number and its absolute value? explain.
2.78 left of x = 0
+ 2.78 right of x = 0
= 2.78 * 2
sketch it !
d = 2.78-(-2.78) = 2.78+2.78 =
To find the distance on the number line between a negative number and its absolute value, we need to understand what the absolute value represents.
The absolute value of a number is its distance from zero on the number line, regardless of whether the number is positive or negative.
In this case, the absolute value of the negative number is given as 2.78, meaning that the negative number is 2.78 units away from zero.
To find the distance between the negative number and its absolute value, we can subtract the absolute value from the negative number.
Let's assume the negative number is represented as -x, where x is the absolute value.
Therefore, -x - x = -2x
We know that -2x = 2.78
To find the value of x, we need to solve for x.
Divide both sides of the equation by -2:
(-2x)/-2 = 2.78/-2
x = -1.39
So the absolute value (x) is -1.39 and the negative number (-x) is -(-1.39) which simplifies to 1.39.
Now, to find the distance on the number line between the two, we subtract the negative number from its absolute value:
1.39 - (-1.39) = 2.78
Therefore, the distance on the number line between the negative number and its absolute value is 2.78.