Will you please help me write this equation in net ionic form of this equation and oxidation and reduction reaction, and oxidizing and reducing agent
. 2Na2S2O3 + I2 Na2S4O6 + 2NaI
2Na2S2O3 + I2 Na2S4O6 + 2NaI
2[S2O3]^2- + I2 ==> [S4O6]^2- + 2I^-
I2 on the left has oxidation state of zero. On the right it is 1- EACH. That is a gain of electrons. A gain of electrons is reduction and that makes I2 the oxidizing agent. [S2O3]^2- is oxidized and is the reducing agent.