A portion of the high-resolution emission spectrum of a one-electron atomic species is shown below. The highest energy series is shown on the right, and there many more series at lower wavenumbers, which are not shown. The series in the middle starts at 243860.7015 cm-1 and terminates at 438949.2627 cm-1. Calculate the wavenumber of the peak marked with an asterisk and enter it in the blank below with the correct number of significant figures, but do not enter the units. For this problem maintain all the number of significant figures that are justified by the significant figures rules.
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To find the wavenumber of the peak marked with an asterisk, we need to calculate the average of the starting and ending wavenumbers of the middle series.
Average wavenumber = (243860.7015 cm-1 + 438949.2627 cm-1) / 2
Let's perform the calculation:
Average wavenumber = (243860.7015 + 438949.2627) / 2
Average wavenumber = 682809.9642 / 2
Average wavenumber = 341404.9821 cm-1
Therefore, the wavenumber of the peak marked with an asterisk is 341404.9821 cm-1.
To calculate the wavenumber of the peak marked with an asterisk, we need to determine the midpoint between the starting and terminating points of the middle series.
Start by finding the midpoint. We can use the formula for the midpoint of a range:
Midpoint = (Starting point + Terminating point) / 2
Midpoint = (243860.7015 cm^(-1) + 438949.2627 cm^(-1)) / 2
Calculating this expression gives us:
Midpoint = 682404.9641 cm^(-1)
Therefore, the wavenumber of the peak marked with an asterisk is 682404.9641 cm^(-1).
Make sure to remove the units, as instructed, and report the wavenumber with the correct number of significant figures.