displaces 35.6kn . what weight of water would this boat didplace if it were. floating in salt water of density 1024 kg/m
To calculate the weight of water displaced by the boat, we need to use Archimedes' principle. According to this principle, the weight of the water displaced by an object is equal to the buoyant force acting on that object. The buoyant force can be calculated by multiplying the volume of the water displaced by the object by the density of the water.
First, we need to find the volume of water displaced by the boat. We can use the formula:
Volume = Displacement / Density
In this case, the displacement of the boat is given as 35.6 kN (kilonewtons), which needs to be converted into metric units. Since 1 kN = 1000 N (newtons), the displacement can be converted as follows:
Displacement = 35.6 kN * 1000 N/kN = 35,600 N
Now we can calculate the volume of water displaced:
Volume = 35,600 N / 1024 kg/m³
The result will be in cubic meters (m³).
Finally, to calculate the weight of the water displaced, we can multiply the volume by the density of the water:
Weight = Volume * Density = Volume * 1024 kg/m³
The weight will be in kilograms (kg), representing the weight of the water displaced by the boat when floating in salt water of density 1024 kg/m³.