A cyclist rides at 16 kmh - 1 in a direction 60 degree east of north find the components of his velocity in the direction due to north and due to east
Pls what is the answer
draw the diagram
east = 16 sin60°
north = 16 cos60°
To find the components of the cyclist's velocity in the due north and due east directions, we need to use trigonometry.
First, let's label the given information:
Velocity of the cyclist = 16 km/h
Direction of the cyclist = 60 degrees east of north
Now, we can break down the given velocity into its north and east components.
Step 1: Find the north component of the velocity.
To find the north component, we need to find the horizontal distance traveled by the cyclist in a direction due north.
We can do this by using the cosine function:
North component = Velocity * cos(angle)
North component = 16 km/h * cos(60 degrees)
North component = 16 km/h * 0.5
North component = 8 km/h
Step 2: Find the east component of the velocity.
To find the east component, we need to find the vertical distance traveled by the cyclist in a direction due east.
We can do this by using the sine function:
East component = Velocity * sin(angle)
East component = 16 km/h * sin(60 degrees)
East component = 16 km/h * √3/2
East component = 8√3 km/h
So, the components of the cyclist's velocity in the due north and due east directions are:
North component = 8 km/h
East component = 8√3 km/h