The sides of a triangle are xcm, (x +3)cm and 10cm. If x is a whole number of cm, find the lowest value of x. Options
(A)
3
(B)
4
(C)
5
(D)
6
In any triangle, the sum of two sides must be greater than the third side
xcm, (x +3)cm and 10
x + x+3 > 10 ----> x > 3.5
x + 10 > x+3 ---> 10 > 3 , which is true
x+3 + 10 > x ---> 13 > 0 , yup, true also
so
x > 3.5
But x is supposed to be a whole number, so
x = 4 is the lowest whole number we can use
thank you so much
To find the lowest value of x, we need to determine which value of x will make the sides of the triangle valid.
In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side.
Using this information, we can set up the following inequality:
x + (x + 3) > 10
Simplifying the inequality, we get:
2x + 3 > 10
Subtracting 3 from both sides, we have:
2x > 7
Dividing both sides by 2, we get:
x > 7/2
Since x must be a whole number, we round up to the nearest whole number.
Therefore, the lowest value of x is 4.
So, the correct answer is (B) 4.