Calculate the no. of moles of solute present in 1.25cm cune of 0.5m h3po4
You must mean 1.25 cm^3.
I have no idea what cune is.
You must mean 0.5 M and not 0.05 m. I will assume you meant 0.5 M.
mols H3PO4 = M x L = ?. That's 0.5 M x (1.25 cm^3/1000 cm^3) = ?
answer is 625 cm3
To calculate the number of moles of solute, we can use the formula:
Moles = Concentration (mol/L) x Volume (L)
First, we need to convert the volume from cm³ to L:
1 cm³ = 1 × 10⁻³ L
Given that the volume is 1.25 cm³, we can convert it to L:
1.25 cm³ = 1.25 × 10⁻³ L
Next, we can substitute the values into the formula:
Moles = 0.5 mol/L x 1.25 × 10⁻³ L
Now, we can calculate the number of moles:
Moles = 0.5 x 1.25 × 10⁻³
Moles = 0.625 × 10⁻³
Moles = 6.25 × 10⁻⁴
Therefore, the number of moles of solute present in 1.25 cm³ of 0.5 M H₃PO₄ is 6.25 × 10⁻⁴ moles.
To calculate the number of moles of solute present in a solution, you need to know the volume of the solution and the molarity of the solute.
In this case, you have the volume of the solution (1.25 cm^3) and the molarity of the solute (0.5 M H3PO4). However, we need to convert the volume from cm^3 to liters (L) and the molarity from M to moles per liter (mol/L).
1. Convert the volume from cm^3 to liters:
Since 1 cm^3 is equal to 1 milliliter (mL), we divide the volume by 1000 to convert it to liters.
1.25 cm^3 ÷ 1000 = 0.00125 L
2. Convert the molarity from M to mol/L:
The molarity (M) represents the number of moles of solute per liter of solution. Therefore, we keep the molarity as it is.
0.5 M
3. Now, you can use the formula: moles = volume (L) x molarity (mol/L)
moles = 0.00125 L x 0.5 mol/L
Calculating the result:
moles = 0.000625 mol
Hence, there are 0.000625 moles of H3PO4 in 1.25 cm^3 of a 0.5 M H3PO4 solution.