A student travels 8km north and then 5km east. What is then her bearing from her starting point?
D = 5 + 8i
Tan A = x/y = 5/8.
A =
To determine the bearing from the starting point, we need to calculate the angle formed between the original position and the final position of the student.
To do this, we make use of trigonometry. We have traveled 8km north and 5km east, forming a right-angled triangle. The north direction is the opposite side, the east direction is the adjacent side, and the hypotenuse represents the displacement from the starting point to the final position.
Using the Pythagorean theorem, we can find the hypotenuse of the right-angled triangle:
Hypotenuse = √(8^2 + 5^2)
= √(64 + 25)
= √89
≈ 9.43 km
Next, we can find the angle by using the inverse tangent function (tan^(-1)):
Angle = tan^(-1)(opposite/adjacent)
= tan^(-1)(8/5)
≈ 57.99 degrees
Therefore, the student's bearing from her starting point is approximately 58 degrees east of north.
2+2
032degree
D=√(8^2+5^2)
√(64+25)=
√89=9.43m
To find the bearing of the starting point, we need to use trigonometry. We can use the tangent function to find the angle that the student traveled from her starting point.
Let A be the angle between the student's path and due north. Then:
tan(A) = opposite/adjacent = 5/8
A = tan^-1(5/8) ≈ 32.05 degrees
So the bearing from her starting point is 32.05 degrees east of due north.