A body of mass 4.0 kg moving with a speed of 2.5 m/s collides with a stationary body of mass 0.2 kg. if the two bodies stick together after collision, calculate the magnitude of the velocity with which they move.?
Given: M1 = 4kg, V1 = 2.5m/s.
M2 = 0.2kg, V2 = 0.
V3 = velocity of M1 and M2 after collision.
Momentum before = Momentum after.
M1*V1+M2*V2 = M 1*V3+M2*V3
4*2.5+0.2*0 = 4V3+0.2V3
4.2V3 = 10
V3 = 2.4 m/s.
conserve momentum.
4.0*2.5 + 0.2*0 = (4.0+0.2)*v
A body of mass 4.0kg move with a velocity of 6m/s calculate the momentum of the body
To calculate the magnitude of the velocity with which the bodies move after collision, we can use the principle of conservation of momentum.
The conservation of momentum states that the total momentum before the collision is equal to the total momentum after the collision.
The momentum of an object is calculated by multiplying its mass by its velocity. So, we can calculate the momentum of the first body before the collision as:
Momentum of the first body = mass * velocity
= 4.0 kg * 2.5 m/s
= 10.0 kg*m/s
Since the second body is stationary, its momentum before the collision is zero:
Momentum of the second body = mass * velocity
= 0.2 kg * 0 m/s
= 0 kg*m/s
The total momentum before the collision is the sum of the individual momenta of the two bodies:
Total momentum before collision = Momentum of the first body + Momentum of the second body
= 10.0 kg*m/s + 0 kg*m/s
= 10.0 kg*m/s
Since the two bodies stick together after the collision, they move together as a single entity. Let's call the final velocity of the combined bodies as V.
So, the total momentum after the collision is the total mass of the combined bodies multiplied by their final velocity:
Total momentum after collision = (mass of first body + mass of second body) * V
Using the given masses, we have:
Total momentum after collision = (4.0 kg + 0.2 kg) * V
= 4.2 kg * V
Since the total momentum before the collision is equal to the total momentum after the collision, we can write:
10.0 kg*m/s = 4.2 kg * V
Now, we can solve for V:
V = (10.0 kg*m/s) / (4.2 kg)
V ≈ 2.38 m/s
Therefore, the magnitude of the velocity with which the bodies move after the collision is approximately 2.38 m/s.