Calculate the value of Keq for the following equation.
Heat + N2(g) + 3H2(g) ↔ 2NH3(g)
[N2] = .533M
[H2] = 1.600M
[NH3] = 0.933M
Bob if you're here, can you tell me if adding a substance like "Heat" to the equation changes the whole problem? Or does it have no effect.
Adding heat to the equation has no effect on calculating this BECAUSE heat is not in the Keq constant.
Keq = (NH3)^2/(N2)(H2)^3 ; note no heat in Keq.
Just plug in the numbers and solve for Keq. A word of caution. The problem does NOT say the system is at equilibrium. You must assume it is at equilibrium in order to use those numbers in the calculation.
Back to the heat being added. That tells you two things. One is that it is an endothermic reaction (needs heat to go) AND it tells you which way the equilibrium will shift if heat is added to the system or taken out of the system.
thank you.
To calculate the value of Keq for the given equation, we need to use the concentrations of reactants and products at equilibrium. Keq represents the equilibrium constant and is determined by the ratio of product concentrations to reactant concentrations at equilibrium.
In this equation, the reaction involves the formation of ammonia (NH3) from nitrogen gas (N2) and hydrogen gas (H2). The balanced equation for the reaction is:
N2(g) + 3H2(g) ↔ 2NH3(g)
To calculate Keq, we need to first determine the equilibrium concentrations of N2, H2, and NH3. Given the concentrations:
[N2] = 0.533 M
[H2] = 1.600 M
[NH3] = 0.933 M
Keq can be calculated using the equation:
Keq = ([NH3]^2) / ([N2] * [H2]^3)
Substituting the given concentrations into the equation, we get:
Keq = (0.933^2) / (0.533 * 1.600^3)
Calculating this expression results in the value of Keq for the given reaction.
Regarding the substance "Heat" in the equation, it is shown above the reaction arrow to indicate that the reaction is being carried out under specific conditions, such as with the input of heat or at a specific temperature. Heat, in this context, does not affect the calculation of Keq, as the equilibrium constant is only dependent on the concentrations of the reactants and products at equilibrium. The presence of heat in the equation implies that the reaction is being conducted under particular thermal conditions, but it doesn't have an impact on the calculation of Keq.