Baking powder is stoichiometrically matched between baking soda and tartaric acid, and 1/3 of the mass of baking powder is baking soda -- this is because the molecular weight of cream of tartar is roughly twice that of baking soda. If the density of baking powder is 1 g/mL, compute the number of moles of baking soda that are contributed by the baking powder. Enter your answer as a number, without including units.
A similar problem/solution to study. https://www.bartleby.com/solution-answer/chapter-9-problem-17alq-introductory-chemistry-a-foundation-9th-edition/9781337399425/baking-powder-is-a-mixture-of-cream-of-tartar-khc4h4o6and-baking-soda-nahco3-when-it-is-placed/b7828909-2534-11e9-8385-02ee952b546e
To calculate the number of moles of baking soda contributed by the baking powder, we first need to determine the mass of baking soda in the baking powder.
Given that 1/3 of the mass of baking powder is baking soda, and the density of baking powder is 1 g/mL, we can set up the following equation:
Mass of baking soda = (1/3) * Mass of baking powder
Since the density of baking powder is 1 g/mL, the mass of baking powder is equal to the volume of baking powder in mL.
Thus, we can rewrite the equation as:
Mass of baking soda = (1/3) * Volume of baking powder
Since density = mass/volume, we can rearrange the equation to solve for volume:
Volume of baking powder = Mass of baking powder / density
Substituting this into the equation for the mass of baking soda:
Mass of baking soda = (1/3) * (Mass of baking powder / density)
Next, we need to determine the molecular weight of baking soda.
The molecular weight of baking soda (NaHCO3) is calculated as follows:
Molecular weight of Na = 22.99 g/mol
Molecular weight of H = 1.01 g/mol
Molecular weight of C = 12.01 g/mol
Molecular weight of O = 16.00 g/mol
Summing up the atomic masses:
Molecular weight of baking soda = (22.99 + 1.01 + 12.01 + (3 * 16.00)) g/mol = 84.01 g/mol
To calculate the number of moles of baking soda, we divide the mass of baking soda by its molecular weight:
Number of moles of baking soda = Mass of baking soda / Molecular weight of baking soda
Plugging in the values:
Number of moles of baking soda = ((1/3) * (Mass of baking powder / density)) / Molecular weight of baking soda
Given that the density of baking powder is 1 g/mL, we can simplify the equation to:
Number of moles of baking soda = (Mass of baking powder / 3) / Molecular weight of baking soda
Purely in terms of numbers, the equation becomes:
Number of moles of baking soda = (Mass of baking powder / 3) / 84.01
Please provide the mass of baking powder.
To compute the number of moles of baking soda contributed by the baking powder, we need to know the total mass of the baking powder and the molar mass of baking soda.
Given:
Density of baking powder = 1 g/mL
1/3 of the mass of baking powder is baking soda
To start, we can assume a convenient value for the mass of the baking powder. Let's say we have 1 gram of baking powder.
Since the density of baking powder is 1 g/mL, this means that 1 gram of baking powder has a volume of 1 mL.
Since 1/3 of the mass of baking powder is baking soda, this means that 1/3 of the 1 gram of baking powder is baking soda, which is equal to 1/3 gram or 0.333 grams of baking soda.
Now, let's find the molar mass of baking soda. The molar mass of baking soda (NaHCO3) is approximately 84 grams/mole.
To calculate the number of moles of baking soda, we can use the formula:
Number of moles = Mass / Molar mass
Number of moles of baking soda = 0.333 grams / 84 grams/mole
Number of moles of baking soda = 0.00396 moles
Therefore, the number of moles of baking soda contributed by the baking powder is approximately 0.00396 moles.