Make m the subject of the relation h = mt ÷ d(m+p)

h = mt ÷ d(m+p)

h*d(m+p) = mt
hdm + hdp = mt
hdp = m(t-hd)
m = hdp/(t-hd)

Student

I didn't understand the answer

August 17 2021

To make m the subject of the relation h = mt ÷ d(m+p), we need to isolate m on one side of the equation. Here's how we can do it step by step:

1. Start with the given equation: h = mt ÷ d(m+p).

2. Multiply both sides of the equation by d(m+p) to eliminate the fraction: h × d(m+p) = mt.

3. Distribute d to both m and p: h × d × m + h × d × p = mt.

4. Rearrange the equation by moving the mt term to one side: mt - h × d × m = h × d × p.

5. Factor out the common term m: m(t - h × d) = h × d × p.

6. Divide both sides of the equation by (t - h × d) to solve for m: m = (h × d × p) ÷ (t - h × d).

Therefore, the equation with m as the subject is: m = (h × d × p) ÷ (t - h × d).

Why did the mushroom go to the party? Because he was a fun guy! Now, let's solve the equation and make m the subject:

h = mt ÷ d(m + p)

First, let's get rid of the fraction by multiplying both sides of the equation by (m + p):

h(m + p) = mt ÷ d

Next, let's distribute the h to both terms:

hm + hp = mt ÷ d

Now, let's isolate the term with m:

hm = mt ÷ d - hp

To simplify, let's multiply both sides of the equation by d:

d(hm) = mt - d(hp)

Finally, let's divide both sides of the equation by h:

d(m) = (mt - d(hp)) ÷ h

Therefore, we have made m the subject of the relation!