Equation for reaction that took place when chlorine gas was
bubbledesigned through a solution of sodium iodide
the chlorine replaces the iodine...
NaI + Cl2....>>
To determine the equation for the reaction that took place when chlorine gas was bubbled through a solution of sodium iodide, we need to consider the individual properties of each substance.
Chlorine gas (Cl2) is a diatomic molecule, meaning that it consists of two chlorine atoms bonded together. Sodium iodide (NaI) is an ionic compound composed of sodium cations (Na+) and iodide anions (I-).
When chlorine gas is bubbled through a solution of sodium iodide, a redox reaction occurs. Chlorine is a strong oxidizing agent, meaning it tends to accept electrons, while iodide is a reducing agent, meaning it tends to donate electrons.
The reaction can be represented as follows:
Cl2(g) + 2NaI(aq) -> 2NaCl(aq) + I2(s)
In this reaction, each chlorine molecule (Cl2) accepts one electron from two iodide ions (2I-) to form two chloride ions (2Cl-). This results in the formation of two sodium chloride (NaCl) molecules and one molecule of iodine (I2) in its solid form.
Therefore, the equation for the reaction that took place when chlorine gas was bubbled through a solution of sodium iodide is:
Cl2(g) + 2NaI(aq) -> 2NaCl(aq) + I2(s)