When 0.08 moles of ammonium sulfate
((NH4)2SO4) are dissolved in enough water
to make 298 milliliters of solution, how many
ammonium ions are present?
0.08 mols (NH4)2SO4 contains 0.08*2 mols NH4^+. There are 6.02E23 ions in a mole of ions. You do the math.
To find out how many ammonium ions are present, we need to determine the number of moles of ammonium ions in 0.08 moles of ammonium sulfate.
Ammonium sulfate, (NH4)2SO4, contains two ammonium ions [(NH4)+] per molecule. This means that for every mole of ammonium sulfate, we have 2 moles of ammonium ions.
Since we have 0.08 moles of ammonium sulfate, we can multiply this by the mole ratio of ammonium ions to ammonium sulfate to find the number of moles of ammonium ions:
Number of moles of ammonium ions = 0.08 moles × 2 moles of ammonium ions / 1 mole of ammonium sulfate
= 0.16 moles of ammonium ions
Now, to find the number of ammonium ions present, we need to convert moles to the number of entities using Avogadro's number. Avogadro's number is approximately 6.022 × 10^23 entities per mole.
Number of ammonium ions = 0.16 moles × 6.022 × 10^23 entities/mole
= 9.6352 × 10^22 ammonium ions
Therefore, there are approximately 9.6352 × 10^22 ammonium ions present in the solution.