.Balance the chemical equation given: zinc oxide+ sulphuric (vi) acid
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ZnO+H2SO4----------> ZnSO+H2O
To balance the chemical equation for the reaction between zinc oxide and sulfuric acid, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's how you can balance it:
Zinc oxide: ZnO
Sulfuric acid: H2SO4
1. Start by writing the unbalanced equation:
ZnO + H2SO4 -> ?
2. Balance the zinc atoms. Since there is only one zinc atom on the left side, place a coefficient of 1 in front of ZnO on the right side:
ZnO + H2SO4 -> ZnO + ?
3. Balance the sulfur atoms. Since there is one sulfur atom on the right side (in sulfuric acid), place a coefficient of 1 in front of H2SO4 on the left side:
ZnO + 1H2SO4 -> ZnO + ?
4. Balance the oxygen atoms. There is one oxygen atom in ZnO and four oxygen atoms in H2SO4. Therefore, you will need 4 ZnO on the right side to balance the oxygen.
ZnO + 1H2SO4 -> 4ZnO + ?
5. Next, balance the hydrogen atoms. Since there are two hydrogen atoms in H2SO4, you will need 2 H2SO4 on the left side to balance the hydrogen.
ZnO + 2H2SO4 -> 4ZnO + ?
6. Finally, verify the balance of the equation by checking the number of atoms on both sides. The balanced equation is:
ZnO + 2H2SO4 -> 4ZnSO4 + H2O
Now, the equation is balanced with equal numbers of each element on both sides. The reaction produces zinc sulfate (ZnSO4) and water (H2O).