Calculate the mass of zinc oxide when 0.1mole of zinc trioxocarbonate (iv)is heated strongly.
I assume you mean zinc carbonate or ZnCO3. You don't need all that gibberish to name ZnCO3.
ZnCO3 ==> ZnO + CO2
0.1 mol ZnCO3 will release 0.1 mol CO2.
Then grams CO2 = mols x molar mass CO2 = ?
wat is d answer
To calculate the mass of zinc oxide produced when 0.1 mole of zinc trioxocarbonate (IV) is heated strongly, you will need to use the stoichiometry of the reaction. Here's how you can do it:
1. Write the balanced equation for the reaction:
ZnCO3 → ZnO + CO2
2. Determine the molar ratio between zinc trioxocarbonate (IV) (ZnCO3) and zinc oxide (ZnO) from the balanced equation:
From the equation, you can see that 1 mole of ZnCO3 produces 1 mole of ZnO.
3. Convert the given amount of zinc trioxocarbonate (IV) into moles:
Since you have 0.1 mole of ZnCO3, you don't need to convert.
4. Use the molar ratio to find the number of moles of zinc oxide produced:
Since the molar ratio from the balanced equation is 1:1, you will have 0.1 mole of ZnO.
5. Find the molar mass of zinc oxide (ZnO):
The molar mass of zinc (Zn) is 65.38 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol. Therefore, the molar mass of ZnO is 81.38 g/mol.
6. Calculate the mass of zinc oxide produced:
Multiply the number of moles of ZnO (0.1 mole) by its molar mass (81.38 g/mol):
Mass of ZnO = 0.1 mole * 81.38 g/mol = 8.138 g
Therefore, the mass of zinc oxide produced when 0.1 mole of zinc trioxocarbonate (IV) is heated strongly is approximately 8.138 grams.