On a certain project, an employer lacked six days of working twice as many days as did his employee. If the sum of the days they worked is 42, how many days did each work?
Employee= 16 hours
Employer= 26 hours
Okay but the process where????
Let's assume that the employer worked for x days and the employee worked for y days.
According to the problem, the employer lacked six days of working twice as many days as the employee. This can be expressed as:
x = 2y + 6 ---(Equation 1)
Also, the sum of the days they worked is 42, which can be written as:
x + y = 42 ---(Equation 2)
Now, we can solve these equations simultaneously to find the values of x and y.
Substituting the value of x from Equation 1 into Equation 2, we get:
(2y + 6) + y = 42
3y + 6 = 42
3y = 42 - 6
3y = 36
y = 36/3
y = 12
Using Equation 2, we can substitute the value of y back to find the value of x:
x + 12 = 42
x = 42 - 12
x = 30
So, the employer worked for 30 days, and the employee worked for 12 days.
To solve this problem, we will set up a system of equations based on the given information.
Let's assume that the employer worked for x days, and the employee worked for y days.
We are given that the employer lacked six days of working twice as many days as the employee. This can be expressed as:
x = 2y + 6 (Equation 1)
We are also given that the sum of the days they worked is 42:
x + y = 42 (Equation 2)
Now, we have a system of two equations:
x = 2y + 6 (Equation 1)
x + y = 42 (Equation 2)
To solve this system of equations, we can use the substitution method:
1. Solve Equation 1 for x:
x = 2y + 6
2. Substitute the value of x in Equation 2:
(2y + 6) + y = 42
3. Simplify and solve for y:
3y + 6 = 42
3y = 42 - 6
3y = 36
y = 12
Now that we have found the value of y, we can substitute it back into Equation 2 to find the value of x:
x + 12 = 42
x = 42 - 12
x = 30
Therefore, the employer worked for 30 days, and the employee worked for 12 days.