When a number is squared it is equal to that number times 5. What is a possible solution. Pls explain i dont understand
I think the answer is x^2/5x=0. Is this correct or is the answer x^2 - 5x = 0?
the 2nd one
To find a possible solution to the equation "When a number is squared, it is equal to that number times 5," we can represent the number as a variable and solve for it. Let's call the number "x."
According to the equation, when the number "x" is squared, it is equal to "x" times 5. Mathematically, we can write this as:
x^2 = 5x
To find "x," we can rearrange the equation and solve for the variable. Let's subtract 5x from both sides of the equation:
x^2 - 5x = 0
Now, notice that both terms on the left side have a common factor of "x." We can factor out the "x":
x(x - 5) = 0
To satisfy this equation, either "x = 0" or "(x - 5) = 0." Let's solve both possibilities.
For "x = 0," we substitute it back into the original equation:
0^2 = 5(0)
0 = 0
This shows that "x = 0" is a solution to the equation.
For "(x - 5) = 0," we solve for "x":
x - 5 = 0
x = 5
Substituting "x = 5" back into the original equation:
(5)^2 = 5(5)
25 = 25
This shows that "x = 5" is also a solution to the equation.
Therefore, the possible solutions to the equation "When a number is squared, it is equal to that number times 5" are "x = 0" and "x = 5."