What is the molarity of a solution that contains 25.0 g of HCL in 150.0 mL of solution?
Please show work.
To find the molarity (M) of a solution, you need to divide the number of moles of solute by the volume of the solution in liters.
First, calculate the number of moles of HCl using its molar mass:
Molar mass of HCl = 1.01 g/mol (molar mass of H) + 35.45 g/mol (molar mass of Cl) = 36.46 g/mol
Number of moles of HCl = mass of HCl / molar mass of HCl
= 25.0 g / 36.46 g/mol
= 0.686 moles
Next, convert the volume of the solution to liters:
150.0 mL = 150.0 mL x (1 L / 1000 mL)
= 0.150 L
Finally, calculate the molarity:
Molarity (M) = moles of solute / volume of solution in liters
= 0.686 moles / 0.150 L
≈ 4.573 M
Therefore, the molarity of the solution is approximately 4.573 M.
M = mols/L
So how many moles do you have? That's grams/molar mass = 25.0/36.45 = ?
Then M = ?mols/0.150 L = ?