Do copper (2) chloride and potassium carbonate form a precipitate?
copperIIcarbonate is not possible in water solutions (and decomposed quickly in air due to water vapor. What is formed in the above reaction nearly always is a carbonated or hydroxide of copperIIchloride, such as Cu2(OH)2CO3 (which occurs naturally as the mineral malachite) or Cu3(OH)2(CO3)2 (azurite). Both of these minerals are insoluble, however, it is very unlikely one would makd this by reaction of the two forms you gave. So my answer is no, the reachtion is basically impossible without water present.
yes.
CuCl2(aq) + K2CO3(aq) ==> CuCO3(solid) + 2KCl(aq)
Bob P's answer is so much more detailed than mine; however, my experience is that a ppt does form but it usually is the hydroxide/carbonate mixture. As far as I know ALL solubility tables list CuCO3 as insoluble in water.
To determine whether copper (II) chloride (CuCl2) and potassium carbonate (K2CO3) will form a precipitate, we need to check the solubility rules for each compound and their respective ions.
Copper (II) chloride:
Copper (II) chloride is a soluble compound. Most chlorides are soluble, except for those of silver, lead (II), and mercury (I) ions. So, CuCl2 will dissociate into copper (II) ions (Cu^2+) and chloride ions (Cl^-) in water.
Potassium carbonate:
Potassium carbonate is also a soluble compound. Most carbonates are insoluble, but exceptions include those of alkali metals (group 1) and ammonium ions. So, K2CO3 will dissociate into potassium ions (K+) and carbonate ions (CO3^2-) in water.
According to the solubility rules, both Cu^2+ and CO3^2- ions are soluble, which means they will remain in solution and not form a precipitate when mixed together.
In conclusion, when copper (II) chloride and potassium carbonate are combined, they will not form a precipitate.