What is the probability of selecting a “B” on the first spinner and a “Z” on the second spinner?
a.1/16
b.1/12
c.1/6
d. 1/4
1/4 * 1/4 = 1/16
Does each spinner have 4 equal-sized pieces?
nu the first one yea the second 3
SOMEONE HELP?
help soup
Did you not read oobleck's reply above??
To determine the probability of selecting a "B" on the first spinner and a "Z" on the second spinner, we need to know the number of equally likely outcomes for each spinner.
Let's say the first spinner has 4 equally likely outcomes: A, B, C, and D. Since we are interested in the probability of selecting a "B" on the first spinner, there is only 1 favorable outcome out of the 4 possibilities.
Now, let's assume the second spinner has 3 equally likely outcomes: X, Y, and Z. We want to know the probability of selecting a "Z" on this spinner, which again has only 1 favorable outcome out of the 3 possibilities.
To find the probability of two independent events occurring together, we multiply their individual probabilities. Therefore, the probability of selecting a "B" on the first spinner and a "Z" on the second spinner is:
(1/4) * (1/3) = 1/12
So, the correct answer is b. 1/12.
How many sections are on each spinner?
And... asking for the answers is cheating.
You would be banned and anyone who answers you would also be banned from this website...