Can somebody expain why my ander wrong?
A spherical conductor of radius 10.0 cm has net charge
Q = 0.78 µC.
Calculate the electric potential at the following distance from its center, assuming the electric potential goes to zero at an infinite distance from the sphere. At 2.7 cm
I use this UE=KQ/r
[8.99*10^9)(.78*10^-6)]/.027=258754V
If you really mean inside the conducting sphere the E field is zero and therefore V is the same as outside on the surface which is the same as the V of a centered point charge at that sphere radius.
To calculate the electric potential at a certain distance from the center of a spherical conductor, you can use the equation:
V = (k * Q) / r
Where:
V is the electric potential
k is the electrostatic constant (8.99 x 10^9 Nm^2/C^2)
Q is the net charge of the conductor
r is the distance from the center of the conductor
In this case, you have a spherical conductor with a radius of 10.0 cm and a net charge of 0.78 µC (which is equal to 0.78 x 10^-6 C). You want to calculate the electric potential at a distance of 2.7 cm from the center.
Plugging in the given values into the formula:
V = (8.99 x 10^9 Nm^2/C^2 * 0.78 x 10^-6 C) / 0.027 m
Converting the radius from cm to m (0.027 m):
V = (8.99 x 10^9 Nm^2/C^2 * 0.78 x 10^-6 C) / 0.027 m
Calculating this equation:
V = 258,754 V (rounded to the nearest whole number)
So, the electric potential at a distance of 2.7 cm from the center of the spherical conductor is approximately 258,754 V.