What is The relative molecular mass of lead ii trioxonitrate v (pb=108,N=14,0=26)
108+2*14+6*16
=108+28+96
=108+124
=232
Pb(no3)2
(Pb=108)
(N=14)
(O=16)
Therefore=108+2*14+6*16
=108+28+96
=232
Yes “232” it is the correct answer Ayo is correct.
Pb(NO 3) 2
molar mass = 108 + 2*14 + 6*16
NOTE oxygen is NOT 26
Pb(NO3)2
Pb= 108, N =14, O=16
108+ (2*14) + ( 3*2*16)
108+28+96
232g/mol.
Pb(No3)2
108+2*14+6*16
108+28+96
108+124
232
If you mean Pb(NO3)2., the correct IUPAC name is lead nitrate. You made a typo for O; that is 16 not 26 You made a typo on Pb; that is 207.2 and not 108
Add the individual masses together; i.e.,
Pb + 2*N + 6*O = ?
207.2 + 2*14 + 6*16 = ?
232mol
PbNO3
1P ,2N ,6O
1×108+2×14+16×6
108 + 28 + 96
=232g