Please help ASAP!!!
Graph the following lines given the equation or y-intercept with an ordered pair, with a y-intercept of 3 and an ordered pair of (3, 4).
Line 1: y-intercept: 3 ordered pair: (3, 4)
Line 2: y=-2x+2
y-1nt. = 3, P(3, 4).
Y = mx+b.
4 = m*3 + 3
m = 1/3.
Eq1: Y = (1/3)x + 3. Graph: P1(0, 3), P2(3, 4)
Eq2: Y = -2x + 2. Graph: P1(0, 2), P2(3, -4).
The point where the lines intersect is the solution.
Standard form:
Eq1: x - 3y = -3.
Eq2: 2x + y = 2.
Correction:
Standard form
Eq1: x - 3y = -9.
Eq2: 2x + y = 2.
Sure, I can help you with that! To graph a line with a given y-intercept and an ordered pair, you'll need to understand a few basic principles.
For Line 1, you're given the y-intercept of 3 and the ordered pair (3, 4). The y-intercept is the point where the line crosses the y-axis, so in this case, it would be a point on the graph with the coordinates (0, 3).
To plot the ordered pair (3, 4), you start at the origin, move 3 units up (since the y-coordinate is 4), and then move 3 units to the right (since the x-coordinate is 3). Once you arrive at this point, mark it on your graph.
Now, to draw the line, you can simply connect the y-intercept (0, 3) and the ordered pair (3, 4) with a straight line. This line represents the equation of Line 1.
Moving on to Line 2, the equation given is y = -2x + 2. This equation is in slope-intercept form, y = mx + b, where m represents the slope of the line and b represents the y-intercept.
In this case, the slope is -2, and the y-intercept is 2. This means that the line will have a slope of -2 (which can be thought of as "rise over run") and crosses the y-axis at the point (0, 2).
To graph Line 2, start at the y-intercept point (0, 2). From there, use the slope of -2 to plot additional points. For example, you can move 1 unit to the right (since the slope tells us the run is 1) and then move 2 units down (since the slope tells us the rise is -2).
Repeat this process to plot a couple more points, and then connect them with a straight line. This line represents the equation of Line 2.
I hope this helps you graph the given lines! Let me know if you have any further questions.